Search a number
-
+
133323112001197 is a prime number
BaseRepresentation
bin11110010100000110110100…
…101110110010111010101101
3122111001120020220111220022101
4132110012310232302322231
5114433331213133014242
61151315443033015101
740040164000516006
oct3624066456627255
9574046226456271
10133323112001197
1139532017aa8838
1212b52ab4554491
135951414259031
1424ccc3191c1ad
1510630905319b7
hex7941b4bb2ead

133323112001197 has 2 divisors, whose sum is σ = 133323112001198. Its totient is φ = 133323112001196.

The previous prime is 133323112001141. The next prime is 133323112001221. The reversal of 133323112001197 is 791100211323331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 118469749753161 + 14853362248036 = 10884381^2 + 3854006^2 .

It is a cyclic number.

It is not a de Polignac number, because 133323112001197 - 211 = 133323111999149 is a prime.

It is a super-3 number, since 3×1333231120011973 (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133323112001117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66661556000598 + 66661556000599.

It is an arithmetic number, because the mean of its divisors is an integer number (66661556000599).

Almost surely, 2133323112001197 is an apocalyptic number.

It is an amenable number.

133323112001197 is a deficient number, since it is larger than the sum of its proper divisors (1).

133323112001197 is an equidigital number, since it uses as much as digits as its factorization.

133323112001197 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20412, while the sum is 37.

The spelling of 133323112001197 in words is "one hundred thirty-three trillion, three hundred twenty-three billion, one hundred twelve million, one thousand, one hundred ninety-seven".