Base | Representation |
---|---|
bin | 111110000101010101… |
… | …1011011000000001100 |
3 | 110202010112000022021000 |
4 | 1330022223123000030 |
5 | 4141021211004012 |
6 | 141125305340300 |
7 | 12426605000316 |
oct | 1741253330014 |
9 | 422115008230 |
10 | 133323141132 |
11 | 515a648a265 |
12 | 21a09797690 |
13 | c7594c9c2c |
14 | 664a98a7b6 |
15 | 3704987ddc |
hex | 1f0aadb00c |
133323141132 has 48 divisors (see below), whose sum is σ = 363844835200. Its totient is φ = 42102043920.
The previous prime is 133323141109. The next prime is 133323141139. The reversal of 133323141132 is 231141323331.
133323141132 is a `hidden beast` number, since 1 + 3 + 332 + 314 + 1 + 13 + 2 = 666.
It is a super-2 number, since 2×1333231411322 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a nude number because it is divisible by every one of its digits.
It is a junction number, because it is equal to n+sod(n) for n = 133323141096 and 133323141105.
It is not an unprimeable number, because it can be changed into a prime (133323141139) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 32484094 + ... + 32488197.
Almost surely, 2133323141132 is an apocalyptic number.
133323141132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
133323141132 is an abundant number, since it is smaller than the sum of its proper divisors (230521694068).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133323141132 is a wasteful number, since it uses less digits than its factorization.
133323141132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 64972323 (or 64972315 counting only the distinct ones).
The product of its digits is 3888, while the sum is 27.
Adding to 133323141132 its reverse (231141323331), we get a palindrome (364464464463).
The spelling of 133323141132 in words is "one hundred thirty-three billion, three hundred twenty-three million, one hundred forty-one thousand, one hundred thirty-two".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •