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13332315131 is a prime number
BaseRepresentation
bin11000110101010101…
…01111101111111011
31021102011002210010022
430122222233233323
5204301033041011
610042541441055
7651246544262
oct143252575773
937364083108
1013332315131
115721820763
122700b7018b
1313461a5485
149069515d9
155306e58db
hex31aaafbfb

13332315131 has 2 divisors, whose sum is σ = 13332315132. Its totient is φ = 13332315130.

The previous prime is 13332315107. The next prime is 13332315133. The reversal of 13332315131 is 13151323331.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13332315131 - 214 = 13332298747 is a prime.

It is a super-2 number, since 2×133323151312 (a number of 21 digits) contains 22 as substring.

Together with 13332315133, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13332315131.

It is not a weakly prime, because it can be changed into another prime (13332315133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6666157565 + 6666157566.

It is an arithmetic number, because the mean of its divisors is an integer number (6666157566).

Almost surely, 213332315131 is an apocalyptic number.

13332315131 is a deficient number, since it is larger than the sum of its proper divisors (1).

13332315131 is an equidigital number, since it uses as much as digits as its factorization.

13332315131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2430, while the sum is 26.

Adding to 13332315131 its reverse (13151323331), we get a palindrome (26483638462).

The spelling of 13332315131 in words is "thirteen billion, three hundred thirty-two million, three hundred fifteen thousand, one hundred thirty-one".