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133324012300 = 22521333240123
BaseRepresentation
bin111110000101010111…
…0101111101100001100
3110202010120122120021111
41330022232233230030
54141021421343200
6141125340141404
712426615256213
oct1741256575414
9422116576244
10133324012300
11515a6a24836
1221a09b37864
13c75974360b
14664ab3607a
153704aab0ba
hex1f0abafb0c

133324012300 has 18 divisors (see below), whose sum is σ = 289313106908. Its totient is φ = 53329604880.

The previous prime is 133324012279. The next prime is 133324012307. The reversal of 133324012300 is 3210423331.

It is a super-3 number, since 3×1333240123003 (a number of 34 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (133324012307) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 666619962 + ... + 666620161.

Almost surely, 2133324012300 is an apocalyptic number.

133324012300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

133324012300 is an abundant number, since it is smaller than the sum of its proper divisors (155989094608).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133324012300 is a wasteful number, since it uses less digits than its factorization.

133324012300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1333240137 (or 1333240130 counting only the distinct ones).

The product of its (nonzero) digits is 1296, while the sum is 22.

Adding to 133324012300 its reverse (3210423331), we get a palindrome (136534435631).

The spelling of 133324012300 in words is "one hundred thirty-three billion, three hundred twenty-four million, twelve thousand, three hundred".

Divisors: 1 2 4 5 10 20 25 50 100 1333240123 2666480246 5332960492 6666200615 13332401230 26664802460 33331003075 66662006150 133324012300