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13332401281 is a prime number
BaseRepresentation
bin11000110101010110…
…00100110010000001
31021102011021011022001
430122223010302001
5204301043320111
610042543344001
7651250353403
oct143253046201
937364234261
1013332401281
11572187a461
122700bb2001
131346205754
14906974b73
155307111c1
hex31aac4c81

13332401281 has 2 divisors, whose sum is σ = 13332401282. Its totient is φ = 13332401280.

The previous prime is 13332401263. The next prime is 13332401309. The reversal of 13332401281 is 18210423331.

It is an a-pointer prime, because the next prime (13332401309) can be obtained adding 13332401281 to its sum of digits (28).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8243005681 + 5089395600 = 90791^2 + 71340^2 .

It is a cyclic number.

It is not a de Polignac number, because 13332401281 - 27 = 13332401153 is a prime.

It is a super-2 number, since 2×133324012812 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13332401231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6666200640 + 6666200641.

It is an arithmetic number, because the mean of its divisors is an integer number (6666200641).

Almost surely, 213332401281 is an apocalyptic number.

It is an amenable number.

13332401281 is a deficient number, since it is larger than the sum of its proper divisors (1).

13332401281 is an equidigital number, since it uses as much as digits as its factorization.

13332401281 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3456, while the sum is 28.

The spelling of 13332401281 in words is "thirteen billion, three hundred thirty-two million, four hundred one thousand, two hundred eighty-one".