Base | Representation |
---|---|
bin | 11110010100001110010000… |
… | …110111000101101010011011 |
3 | 122111002022212121120212220202 |
4 | 132110032100313011222123 |
5 | 114433444043113124242 |
6 | 1151323243430212415 |
7 | 40040565645504056 |
oct | 3624162067055233 |
9 | 574068777525822 |
10 | 133331100129947 |
11 | 395354470a8135 |
12 | 12b545637b410b |
13 | 59520b81a3935 |
14 | 24cd38c7b5a9d |
15 | 10633ab984932 |
hex | 794390dc5a9b |
133331100129947 has 2 divisors, whose sum is σ = 133331100129948. Its totient is φ = 133331100129946.
The previous prime is 133331100129911. The next prime is 133331100130021. The reversal of 133331100129947 is 749921001133331.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133331100129947 is a prime.
It is not a weakly prime, because it can be changed into another prime (133331100120947) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66665550064973 + 66665550064974.
It is an arithmetic number, because the mean of its divisors is an integer number (66665550064974).
Almost surely, 2133331100129947 is an apocalyptic number.
133331100129947 is a deficient number, since it is larger than the sum of its proper divisors (1).
133331100129947 is an equidigital number, since it uses as much as digits as its factorization.
133331100129947 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 367416, while the sum is 47.
The spelling of 133331100129947 in words is "one hundred thirty-three trillion, three hundred thirty-one billion, one hundred million, one hundred twenty-nine thousand, nine hundred forty-seven".
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