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133331100129947 is a prime number
BaseRepresentation
bin11110010100001110010000…
…110111000101101010011011
3122111002022212121120212220202
4132110032100313011222123
5114433444043113124242
61151323243430212415
740040565645504056
oct3624162067055233
9574068777525822
10133331100129947
11395354470a8135
1212b545637b410b
1359520b81a3935
1424cd38c7b5a9d
1510633ab984932
hex794390dc5a9b

133331100129947 has 2 divisors, whose sum is σ = 133331100129948. Its totient is φ = 133331100129946.

The previous prime is 133331100129911. The next prime is 133331100130021. The reversal of 133331100129947 is 749921001133331.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133331100129947 is a prime.

It is not a weakly prime, because it can be changed into another prime (133331100120947) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66665550064973 + 66665550064974.

It is an arithmetic number, because the mean of its divisors is an integer number (66665550064974).

Almost surely, 2133331100129947 is an apocalyptic number.

133331100129947 is a deficient number, since it is larger than the sum of its proper divisors (1).

133331100129947 is an equidigital number, since it uses as much as digits as its factorization.

133331100129947 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 367416, while the sum is 47.

The spelling of 133331100129947 in words is "one hundred thirty-three trillion, three hundred thirty-one billion, one hundred million, one hundred twenty-nine thousand, nine hundred forty-seven".