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13333121101 is a prime number
BaseRepresentation
bin11000110101011011…
…10100100001001101
31021102012121201201001
430122231310201031
5204301234333401
610043011020301
7651256442116
oct143255644115
937365551631
1013333121101
115722221253
12270129a691
1313463c8291
14906ac120d
15530804601
hex31ab7484d

13333121101 has 2 divisors, whose sum is σ = 13333121102. Its totient is φ = 13333121100.

The previous prime is 13333121093. The next prime is 13333121159. The reversal of 13333121101 is 10112133331.

13333121101 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11800476900 + 1532644201 = 108630^2 + 39149^2 .

It is a cyclic number.

It is not a de Polignac number, because 13333121101 - 23 = 13333121093 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13333125101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6666560550 + 6666560551.

It is an arithmetic number, because the mean of its divisors is an integer number (6666560551).

Almost surely, 213333121101 is an apocalyptic number.

It is an amenable number.

13333121101 is a deficient number, since it is larger than the sum of its proper divisors (1).

13333121101 is an equidigital number, since it uses as much as digits as its factorization.

13333121101 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 13333121101 its reverse (10112133331), we get a palindrome (23445254432).

The spelling of 13333121101 in words is "thirteen billion, three hundred thirty-three million, one hundred twenty-one thousand, one hundred one".