Base | Representation |
---|---|
bin | 11000110101011011… |
… | …10110110010100111 |
3 | 1021102012122012110201 |
4 | 30122231312302213 |
5 | 204301240133112 |
6 | 10043011131331 |
7 | 651256511212 |
oct | 143255666247 |
9 | 37365565421 |
10 | 13333130407 |
11 | 5722228243 |
12 | 27012a3b47 |
13 | 13463cc59c |
14 | 906ac4779 |
15 | 530807257 |
hex | 31ab76ca7 |
13333130407 has 2 divisors, whose sum is σ = 13333130408. Its totient is φ = 13333130406.
The previous prime is 13333130387. The next prime is 13333130467. The reversal of 13333130407 is 70403133331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13333130407 - 223 = 13324741799 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13333130467) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6666565203 + 6666565204.
It is an arithmetic number, because the mean of its divisors is an integer number (6666565204).
Almost surely, 213333130407 is an apocalyptic number.
13333130407 is a deficient number, since it is larger than the sum of its proper divisors (1).
13333130407 is an equidigital number, since it uses as much as digits as its factorization.
13333130407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6804, while the sum is 28.
Adding to 13333130407 its reverse (70403133331), we get a palindrome (83736263738).
The spelling of 13333130407 in words is "thirteen billion, three hundred thirty-three million, one hundred thirty thousand, four hundred seven".
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