Base | Representation |
---|---|
bin | 11110010100001110101011… |
… | …001001110001001101110000 |
3 | 122111002101000100121022200001 |
4 | 132110032223021301031300 |
5 | 114434000444024001134 |
6 | 1151323355304435344 |
7 | 40040612613024232 |
oct | 3624165311611560 |
9 | 574071010538601 |
10 | 133331541234544 |
11 | 39535653098594 |
12 | 12b54667478b54 |
13 | 59521586a7783 |
14 | 24cd3d11da252 |
15 | 10633d5567414 |
hex | 7943ab271370 |
133331541234544 has 10 divisors (see below), whose sum is σ = 258329861141960. Its totient is φ = 66665770617264.
The previous prime is 133331541234523. The next prime is 133331541234553. The reversal of 133331541234544 is 445432145133331.
It is a junction number, because it is equal to n+sod(n) for n = 133331541234494 and 133331541234503.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4166610663564 + ... + 4166610663595.
It is an arithmetic number, because the mean of its divisors is an integer number (25832986114196).
Almost surely, 2133331541234544 is an apocalyptic number.
It is an amenable number.
133331541234544 is a deficient number, since it is larger than the sum of its proper divisors (124998319907416).
133331541234544 is an equidigital number, since it uses as much as digits as its factorization.
133331541234544 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8333221327167 (or 8333221327161 counting only the distinct ones).
The product of its digits is 3110400, while the sum is 46.
Adding to 133331541234544 its reverse (445432145133331), we get a palindrome (578763686367875).
The spelling of 133331541234544 in words is "one hundred thirty-three trillion, three hundred thirty-one billion, five hundred forty-one million, two hundred thirty-four thousand, five hundred forty-four".
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