Base | Representation |
---|---|
bin | 11000110101011100… |
… | …01010010000010101 |
3 | 1021102012210020211112 |
4 | 30122232022100111 |
5 | 204301300211013 |
6 | 10043012544405 |
7 | 651260262515 |
oct | 143256122025 |
9 | 37365706745 |
10 | 13333210133 |
11 | 5722282131 |
12 | 2701322105 |
13 | 1346429969 |
14 | 906b05845 |
15 | 530820ba8 |
hex | 31ab8a415 |
13333210133 has 2 divisors, whose sum is σ = 13333210134. Its totient is φ = 13333210132.
The previous prime is 13333210117. The next prime is 13333210139. The reversal of 13333210133 is 33101233331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13184321329 + 148888804 = 114823^2 + 12202^2 .
It is a cyclic number.
It is not a de Polignac number, because 13333210133 - 24 = 13333210117 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13333210099 and 13333210108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13333210139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6666605066 + 6666605067.
It is an arithmetic number, because the mean of its divisors is an integer number (6666605067).
Almost surely, 213333210133 is an apocalyptic number.
It is an amenable number.
13333210133 is a deficient number, since it is larger than the sum of its proper divisors (1).
13333210133 is an equidigital number, since it uses as much as digits as its factorization.
13333210133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1458, while the sum is 23.
Adding to 13333210133 its reverse (33101233331), we get a palindrome (46434443464).
The spelling of 13333210133 in words is "thirteen billion, three hundred thirty-three million, two hundred ten thousand, one hundred thirty-three".
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