Base | Representation |
---|---|
bin | 111110000101101000… |
… | …1110011010001001111 |
3 | 110202011012221110011201 |
4 | 1330023101303101033 |
5 | 4141031244430444 |
6 | 141130305130331 |
7 | 12430056342304 |
oct | 1741321632117 |
9 | 422135843151 |
10 | 133333201999 |
11 | 51601131128 |
12 | 21a110299a7 |
13 | c75b6103ca |
14 | 664c0490ab |
15 | 37057c3dd4 |
hex | 1f0b47344f |
133333201999 has 2 divisors, whose sum is σ = 133333202000. Its totient is φ = 133333201998.
The previous prime is 133333201973. The next prime is 133333202047. The reversal of 133333201999 is 999102333331.
It is a weak prime.
It is an emirp because it is prime and its reverse (999102333331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 133333201999 - 225 = 133299647567 is a prime.
It is a super-2 number, since 2×1333332019992 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133333201919) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66666600999 + 66666601000.
It is an arithmetic number, because the mean of its divisors is an integer number (66666601000).
Almost surely, 2133333201999 is an apocalyptic number.
133333201999 is a deficient number, since it is larger than the sum of its proper divisors (1).
133333201999 is an equidigital number, since it uses as much as digits as its factorization.
133333201999 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 354294, while the sum is 46.
The spelling of 133333201999 in words is "one hundred thirty-three billion, three hundred thirty-three million, two hundred one thousand, nine hundred ninety-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.021 sec. • engine limits •