1333333199981 has 2 divisors, whose sum is σ = 1333333199982. Its totient is φ = 1333333199980.

The previous prime is 1333333199969. The next prime is 1333333200103. The reversal of 1333333199981 is 1899913333331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 697751149225 + 635582050756 = 835315^2 + 797234^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1333333199981 is a prime.

It is a super-2 number, since 2×1333333199981² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1333333199921) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666666599990 + 666666599991.

It is an arithmetic number, because the mean of its divisors is an integer number (666666599991).

Almost surely, 2^{1333333199981} is an apocalyptic number.

It is an amenable number.

1333333199981 is a deficient number, since it is larger than the sum of its proper divisors (1).

1333333199981 is an equidigital number, since it uses as much as digits as its factorization.

1333333199981 is an evil number, because the sum of its binary digits is even.

The product of its digits is 4251528, while the sum is 56.

The spelling of 1333333199981 in words is "one trillion, three hundred thirty-three billion, three hundred thirty-three million, one hundred ninety-nine thousand, nine hundred eighty-one".