Base | Representation |
---|---|
bin | 11110010100010000011011… |
… | …001101000000100100000111 |
3 | 122111002112212100222000020012 |
4 | 132110100123031000210013 |
5 | 114434013321302211124 |
6 | 1151324310021300435 |
7 | 40041010320630032 |
oct | 3624203315004407 |
9 | 574075770860205 |
10 | 133333421132039 |
11 | 39536428263387 |
12 | 12b54ab0b6471b |
13 | 5952397cc035b |
14 | 24cd52cb50019 |
15 | 1063495603e0e |
hex | 79441b340907 |
133333421132039 has 2 divisors, whose sum is σ = 133333421132040. Its totient is φ = 133333421132038.
The previous prime is 133333421132029. The next prime is 133333421132057. The reversal of 133333421132039 is 930231124333331.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133333421132039 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 133333421131987 and 133333421132005.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133333421132029) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66666710566019 + 66666710566020.
It is an arithmetic number, because the mean of its divisors is an integer number (66666710566020).
Almost surely, 2133333421132039 is an apocalyptic number.
133333421132039 is a deficient number, since it is larger than the sum of its proper divisors (1).
133333421132039 is an equidigital number, since it uses as much as digits as its factorization.
133333421132039 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 314928, while the sum is 41.
The spelling of 133333421132039 in words is "one hundred thirty-three trillion, three hundred thirty-three billion, four hundred twenty-one million, one hundred thirty-two thousand, thirty-nine".
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