13333401252 has 84 divisors (see below), whose sum is σ = 35929983516. Its totient is φ = 4324311360.

The previous prime is 13333401241. The next prime is 13333401281. The reversal of 13333401252 is 25210433331.

13333401252 is a `hidden beast` number, since 1 + 3 + 3 + 3 + 3 + 401 + 252 = 666.

It can be written as a sum of positive squares in 2 ways, for example, as 9616548096 + 3716853156 = 98064^2 + 60966^2 .

It is a Harshad number since it is a multiple of its sum of digits (27).

It is an unprimeable number.

It is a polite number, since it can be written in 27 ways as a sum of consecutive naturals, for example, 46102 + ... + 169682.

It is an arithmetic number, because the mean of its divisors is an integer number (427737899).

Almost surely, 2^13333401252 is an apocalyptic number.

13333401252 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13333401252, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (17964991758).

13333401252 is an abundant number, since it is smaller than the sum of its proper divisors (22596582264).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13333401252 is a wasteful number, since it uses less digits than its factorization.

13333401252 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 123640 (or 123623 counting only the distinct ones).

The product of its (nonzero) digits is 6480, while the sum is 27.

Adding to 13333401252 its reverse (25210433331), we get a palindrome (38543834583).

The spelling of 13333401252 in words is "thirteen billion, three hundred thirty-three million, four hundred one thousand, two hundred fifty-two".