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13333455433457 is a prime number
BaseRepresentation
bin1100001000000110111111…
…0111111110111011110001
31202012122222102201122222122
43002001233313332323301
53221423404042332312
644205145503444025
72544211312124645
oct302015767767361
952178872648878
1013333455433457
114280760a98355
1215b41432b6615
13759454a134a3
143414b248cc25
15181c78ec6b72
hexc206fdfeef1

13333455433457 has 2 divisors, whose sum is σ = 13333455433458. Its totient is φ = 13333455433456.

The previous prime is 13333455433307. The next prime is 13333455433523. The reversal of 13333455433457 is 75433455433331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12950274625201 + 383180808256 = 3598649^2 + 619016^2 .

It is an emirp because it is prime and its reverse (75433455433331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13333455433457 - 222 = 13333451239153 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13333455433399 and 13333455433408.

It is not a weakly prime, because it can be changed into another prime (13333455433057) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6666727716728 + 6666727716729.

It is an arithmetic number, because the mean of its divisors is an integer number (6666727716729).

Almost surely, 213333455433457 is an apocalyptic number.

It is an amenable number.

13333455433457 is a deficient number, since it is larger than the sum of its proper divisors (1).

13333455433457 is an equidigital number, since it uses as much as digits as its factorization.

13333455433457 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 40824000, while the sum is 53.

The spelling of 13333455433457 in words is "thirteen trillion, three hundred thirty-three billion, four hundred fifty-five million, four hundred thirty-three thousand, four hundred fifty-seven".