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133336521041 is a prime number
BaseRepresentation
bin111110000101101111…
…0011101100101010001
3110202011110012002001012
41330023132131211101
54141033122133131
6141130504220305
712430126504643
oct1741336354521
9422143162035
10133336521041
1151602a98839
1221a1216a695
13c75c203039
14664c670893
153705c2c52b
hex1f0b79d951

133336521041 has 2 divisors, whose sum is σ = 133336521042. Its totient is φ = 133336521040.

The previous prime is 133336521023. The next prime is 133336521053. The reversal of 133336521041 is 140125633331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 121149244225 + 12187276816 = 348065^2 + 110396^2 .

It is an emirp because it is prime and its reverse (140125633331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 133336521041 - 210 = 133336520017 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 133336520989 and 133336521007.

It is not a weakly prime, because it can be changed into another prime (133336521091) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66668260520 + 66668260521.

It is an arithmetic number, because the mean of its divisors is an integer number (66668260521).

Almost surely, 2133336521041 is an apocalyptic number.

It is an amenable number.

133336521041 is a deficient number, since it is larger than the sum of its proper divisors (1).

133336521041 is an equidigital number, since it uses as much as digits as its factorization.

133336521041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 19440, while the sum is 32.

The spelling of 133336521041 in words is "one hundred thirty-three billion, three hundred thirty-six million, five hundred twenty-one thousand, forty-one".