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133337166814013 is a prime number
BaseRepresentation
bin11110010100010011111010…
…011101101001101100111101
3122111002220112102010100221012
4132110103322131221230331
5114434044004201022023
61151330125424245005
740041202202455451
oct3624237235515475
9574086472110835
10133337166814013
1139537a7a634718
1212b55777470765
135952844019b16
1424cd7a63c2661
151063614390978
hex7944fa769b3d

133337166814013 has 2 divisors, whose sum is σ = 133337166814014. Its totient is φ = 133337166814012.

The previous prime is 133337166814001. The next prime is 133337166814051. The reversal of 133337166814013 is 310418661733331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 123183849787684 + 10153317026329 = 11098822^2 + 3186427^2 .

It is an emirp because it is prime and its reverse (310418661733331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 133337166814013 - 214 = 133337166797629 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133337166814063) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66668583407006 + 66668583407007.

It is an arithmetic number, because the mean of its divisors is an integer number (66668583407007).

Almost surely, 2133337166814013 is an apocalyptic number.

It is an amenable number.

133337166814013 is a deficient number, since it is larger than the sum of its proper divisors (1).

133337166814013 is an equidigital number, since it uses as much as digits as its factorization.

133337166814013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1959552, while the sum is 50.

The spelling of 133337166814013 in words is "one hundred thirty-three trillion, three hundred thirty-seven billion, one hundred sixty-six million, eight hundred fourteen thousand, thirteen".