Base | Representation |
---|---|
bin | 1100001000001100011010… |
… | …0100110011111101001000 |
3 | 1202012210201210210121012122 |
4 | 3002003012210303331020 |
5 | 3221434343431304134 |
6 | 44205550104430412 |
7 | 2544262334012132 |
oct | 302030644637510 |
9 | 52183653717178 |
10 | 13334910025544 |
11 | 4281338083978 |
12 | 15b448a478408 |
13 | 759627197573 |
14 | 3415ad732052 |
15 | 181d11a5202e |
hex | c20c6933f48 |
13334910025544 has 64 divisors (see below), whose sum is σ = 25196872780800. Its totient is φ = 6615894542400.
The previous prime is 13334910025501. The next prime is 13334910025553. The reversal of 13334910025544 is 44552001943331.
It is a super-3 number, since 3×133349100255443 (a number of 40 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13334910025495 and 13334910025504.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3409588949 + ... + 3409592859.
It is an arithmetic number, because the mean of its divisors is an integer number (393701137200).
Almost surely, 213334910025544 is an apocalyptic number.
It is an amenable number.
13334910025544 is a deficient number, since it is larger than the sum of its proper divisors (11861962755256).
13334910025544 is a wasteful number, since it uses less digits than its factorization.
13334910025544 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7914 (or 7910 counting only the distinct ones).
The product of its (nonzero) digits is 777600, while the sum is 44.
Adding to 13334910025544 its reverse (44552001943331), we get a palindrome (57886911968875).
The spelling of 13334910025544 in words is "thirteen trillion, three hundred thirty-four billion, nine hundred ten million, twenty-five thousand, five hundred forty-four".
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