Base | Representation |
---|---|
bin | 111110000110010010… |
… | …0111010100011100001 |
3 | 110202012201221101102001 |
4 | 1330030210322203201 |
5 | 4141102334133133 |
6 | 141132404124001 |
7 | 12430442465464 |
oct | 1741444724341 |
9 | 422181841361 |
10 | 133354989793 |
11 | 51612462673 |
12 | 21a18396601 |
13 | c762c9b4ac |
14 | 6650cbb2db |
15 | 370767987d |
hex | 1f0c93a8e1 |
133354989793 has 2 divisors, whose sum is σ = 133354989794. Its totient is φ = 133354989792.
The previous prime is 133354989769. The next prime is 133354989809. The reversal of 133354989793 is 397989453331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 109406808289 + 23948181504 = 330767^2 + 154752^2 .
It is a cyclic number.
It is not a de Polignac number, because 133354989793 - 213 = 133354981601 is a prime.
It is a super-2 number, since 2×1333549897932 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (133354980793) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66677494896 + 66677494897.
It is an arithmetic number, because the mean of its divisors is an integer number (66677494897).
Almost surely, 2133354989793 is an apocalyptic number.
It is an amenable number.
133354989793 is a deficient number, since it is larger than the sum of its proper divisors (1).
133354989793 is an equidigital number, since it uses as much as digits as its factorization.
133354989793 is an evil number, because the sum of its binary digits is even.
The product of its digits is 66134880, while the sum is 64.
The spelling of 133354989793 in words is "one hundred thirty-three billion, three hundred fifty-four million, nine hundred eighty-nine thousand, seven hundred ninety-three".
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