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133354990049 is a prime number
BaseRepresentation
bin111110000110010010…
…0111010100111100001
3110202012201221101202112
41330030210322213201
54141102334140144
6141132404125105
712430442466311
oct1741444724741
9422181841675
10133354990049
1151612462886
1221a18396795
13c762c9b648
146650cbb441
15370767999e
hex1f0c93a9e1

133354990049 has 2 divisors, whose sum is σ = 133354990050. Its totient is φ = 133354990048.

The previous prime is 133354990039. The next prime is 133354990123. The reversal of 133354990049 is 940099453331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 70023744400 + 63331245649 = 264620^2 + 251657^2 .

It is a cyclic number.

It is not a de Polignac number, because 133354990049 - 28 = 133354989793 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 133354989979 and 133354990006.

It is not a weakly prime, because it can be changed into another prime (133354990019) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66677495024 + 66677495025.

It is an arithmetic number, because the mean of its divisors is an integer number (66677495025).

Almost surely, 2133354990049 is an apocalyptic number.

It is an amenable number.

133354990049 is a deficient number, since it is larger than the sum of its proper divisors (1).

133354990049 is an equidigital number, since it uses as much as digits as its factorization.

133354990049 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1574640, while the sum is 50.

The spelling of 133354990049 in words is "one hundred thirty-three billion, three hundred fifty-four million, nine hundred ninety thousand, forty-nine".