Base | Representation |
---|---|
bin | 1100001000010000101110… |
… | …0010010101011101111111 |
3 | 1202012220201102212012200012 |
4 | 3002010023202111131333 |
5 | 3221444231123114122 |
6 | 44210300554453435 |
7 | 2544333113120036 |
oct | 302041342253577 |
9 | 52186642765605 |
10 | 13336067004287 |
11 | 4281881176155 |
12 | 15b4751a3427b |
13 | 75977caa7c81 |
14 | 34167d26371d |
15 | 181d7d3e07e2 |
hex | c210b89577f |
13336067004287 has 2 divisors, whose sum is σ = 13336067004288. Its totient is φ = 13336067004286.
The previous prime is 13336067004217. The next prime is 13336067004307. The reversal of 13336067004287 is 78240076063331.
13336067004287 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13336067004287 - 210 = 13336067003263 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13336067004217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6668033502143 + 6668033502144.
It is an arithmetic number, because the mean of its divisors is an integer number (6668033502144).
Almost surely, 213336067004287 is an apocalyptic number.
13336067004287 is a deficient number, since it is larger than the sum of its proper divisors (1).
13336067004287 is an equidigital number, since it uses as much as digits as its factorization.
13336067004287 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3048192, while the sum is 50.
The spelling of 13336067004287 in words is "thirteen trillion, three hundred thirty-six billion, sixty-seven million, four thousand, two hundred eighty-seven".
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