Base | Representation |
---|---|
bin | 1100001000011010101110… |
… | …0110100011000100010001 |
3 | 1202020011122121000122122111 |
4 | 3002012223212203010101 |
5 | 3222020231112304441 |
6 | 44211423245305321 |
7 | 2544456502131061 |
oct | 302065346430421 |
9 | 52204577018574 |
10 | 13338752463121 |
11 | 4282a2a030118 |
12 | 15b5181265241 |
13 | 759aba26cb77 |
14 | 341855b8d3a1 |
15 | 181e89052081 |
hex | c21ab9a3111 |
13338752463121 has 2 divisors, whose sum is σ = 13338752463122. Its totient is φ = 13338752463120.
The previous prime is 13338752463119. The next prime is 13338752463241. The reversal of 13338752463121 is 12136425783331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10012724875521 + 3326027587600 = 3164289^2 + 1823740^2 .
It is a cyclic number.
It is not a de Polignac number, because 13338752463121 - 21 = 13338752463119 is a prime.
It is a super-3 number, since 3×133387524631213 (a number of 40 digits) contains 333 as substring.
Together with 13338752463119, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (13338762463121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6669376231560 + 6669376231561.
It is an arithmetic number, because the mean of its divisors is an integer number (6669376231561).
Almost surely, 213338752463121 is an apocalyptic number.
It is an amenable number.
13338752463121 is a deficient number, since it is larger than the sum of its proper divisors (1).
13338752463121 is an equidigital number, since it uses as much as digits as its factorization.
13338752463121 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2177280, while the sum is 49.
The spelling of 13338752463121 in words is "thirteen trillion, three hundred thirty-eight billion, seven hundred fifty-two million, four hundred sixty-three thousand, one hundred twenty-one".
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