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133400234207 is a prime number
BaseRepresentation
bin111110000111101000…
…1100000100011011111
3110202022220002001002002
41330033101200203133
54141200424443312
6141141101552515
712431532165422
oct1741721404337
9422286061062
10133400234207
1151635a55449
1221a2b57573b
13c76c480136
146656cd79b9
15370b6154c2
hex1f0f4608df

133400234207 has 2 divisors, whose sum is σ = 133400234208. Its totient is φ = 133400234206.

The previous prime is 133400234189. The next prime is 133400234213. The reversal of 133400234207 is 702432004331.

It is a strong prime.

It is an emirp because it is prime and its reverse (702432004331) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133400234207 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 133400234207.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133400234267) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66700117103 + 66700117104.

It is an arithmetic number, because the mean of its divisors is an integer number (66700117104).

Almost surely, 2133400234207 is an apocalyptic number.

133400234207 is a deficient number, since it is larger than the sum of its proper divisors (1).

133400234207 is an equidigital number, since it uses as much as digits as its factorization.

133400234207 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12096, while the sum is 29.

Adding to 133400234207 its reverse (702432004331), we get a palindrome (835832238538).

The spelling of 133400234207 in words is "one hundred thirty-three billion, four hundred million, two hundred thirty-four thousand, two hundred seven".