Base | Representation |
---|---|
bin | 111110000111101000… |
… | …1100010111111010101 |
3 | 110202022220002112202111 |
4 | 1330033101202333111 |
5 | 4141200430303211 |
6 | 141141102111021 |
7 | 12431532236461 |
oct | 1741721427725 |
9 | 422286075674 |
10 | 133400244181 |
11 | 51635a61996 |
12 | 21a2b57b471 |
13 | c76c484839 |
14 | 6656cdb4a1 |
15 | 370b618421 |
hex | 1f0f462fd5 |
133400244181 has 2 divisors, whose sum is σ = 133400244182. Its totient is φ = 133400244180.
The previous prime is 133400244113. The next prime is 133400244239. The reversal of 133400244181 is 181442004331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 121738188100 + 11662056081 = 348910^2 + 107991^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133400244181 is a prime.
It is a super-2 number, since 2×1334002441812 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133400044181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66700122090 + 66700122091.
It is an arithmetic number, because the mean of its divisors is an integer number (66700122091).
Almost surely, 2133400244181 is an apocalyptic number.
It is an amenable number.
133400244181 is a deficient number, since it is larger than the sum of its proper divisors (1).
133400244181 is an equidigital number, since it uses as much as digits as its factorization.
133400244181 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9216, while the sum is 31.
The spelling of 133400244181 in words is "one hundred thirty-three billion, four hundred million, two hundred forty-four thousand, one hundred eighty-one".
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