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133402333034153 is a prime number
BaseRepresentation
bin11110010101010000100110…
…101011000011011010101001
3122111100010201221212100102002
4132111100212223003122221
5114441130434224043103
61151420104042420345
740046000113264451
oct3625204653033251
9574303657770362
10133402333034153
113956268022a3a7
1212b663235016b5
135958a2ab935b1
1424d29c9044d61
15106517a430488
hex795426ac36a9

133402333034153 has 2 divisors, whose sum is σ = 133402333034154. Its totient is φ = 133402333034152.

The previous prime is 133402333034147. The next prime is 133402333034167. The reversal of 133402333034153 is 351430333204331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 97590630167209 + 35811702866944 = 9878797^2 + 5984288^2 .

It is a cyclic number.

It is not a de Polignac number, because 133402333034153 - 216 = 133402332968617 is a prime.

It is not a weakly prime, because it can be changed into another prime (133402333034053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66701166517076 + 66701166517077.

It is an arithmetic number, because the mean of its divisors is an integer number (66701166517077).

Almost surely, 2133402333034153 is an apocalyptic number.

It is an amenable number.

133402333034153 is a deficient number, since it is larger than the sum of its proper divisors (1).

133402333034153 is an equidigital number, since it uses as much as digits as its factorization.

133402333034153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 349920, while the sum is 38.

Adding to 133402333034153 its reverse (351430333204331), we get a palindrome (484832666238484).

The spelling of 133402333034153 in words is "one hundred thirty-three trillion, four hundred two billion, three hundred thirty-three million, thirty-four thousand, one hundred fifty-three".