Base | Representation |
---|---|
bin | 11110010101010000110001… |
… | …011101011011000110011100 |
3 | 122111100011012120101220022122 |
4 | 132111100301131123012130 |
5 | 114441131322041314044 |
6 | 1151420134025402112 |
7 | 40046004441460403 |
oct | 3625206135330634 |
9 | 574304176356278 |
10 | 133402514010524 |
11 | 395627633a9650 |
12 | 12b66374039338 |
13 | 5958a595199c5 |
14 | 24d2a050b463a |
15 | 106518b27cdee |
hex | 79543175b19c |
133402514010524 has 24 divisors (see below), whose sum is σ = 254679222310128. Its totient is φ = 60637102663040.
The previous prime is 133402514010503. The next prime is 133402514010641. The reversal of 133402514010524 is 425010415204331.
It is a super-3 number, since 3×1334025140105243 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3358139 + ... + 16675794.
It is an arithmetic number, because the mean of its divisors is an integer number (10611634262922).
Almost surely, 2133402514010524 is an apocalyptic number.
It is an amenable number.
133402514010524 is a deficient number, since it is larger than the sum of its proper divisors (121276708299604).
133402514010524 is a wasteful number, since it uses less digits than its factorization.
133402514010524 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20185285 (or 20185283 counting only the distinct ones).
The product of its (nonzero) digits is 57600, while the sum is 35.
Adding to 133402514010524 its reverse (425010415204331), we get a palindrome (558412929214855).
The spelling of 133402514010524 in words is "one hundred thirty-three trillion, four hundred two billion, five hundred fourteen million, ten thousand, five hundred twenty-four".
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