Base | Representation |
---|---|
bin | 10011011010011010100… |
… | …100011001110000001101 |
3 | 11201112101001121211210211 |
4 | 103122122210121300031 |
5 | 133324044433030233 |
6 | 2500502451002421 |
7 | 165244404134614 |
oct | 23323244316015 |
9 | 4645331554724 |
10 | 1334033095693 |
11 | 47483a9a4761 |
12 | 196664b99411 |
13 | 98a4cbcac9c |
14 | 487d34c087b |
15 | 24a7bb605cd |
hex | 1369a919c0d |
1334033095693 has 2 divisors, whose sum is σ = 1334033095694. Its totient is φ = 1334033095692.
The previous prime is 1334033095673. The next prime is 1334033095729. The reversal of 1334033095693 is 3965903304331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1311890762884 + 22142332809 = 1145378^2 + 148803^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1334033095693 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1334033095613) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 667016547846 + 667016547847.
It is an arithmetic number, because the mean of its divisors is an integer number (667016547847).
Almost surely, 21334033095693 is an apocalyptic number.
It is an amenable number.
1334033095693 is a deficient number, since it is larger than the sum of its proper divisors (1).
1334033095693 is an equidigital number, since it uses as much as digits as its factorization.
1334033095693 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2361960, while the sum is 49.
The spelling of 1334033095693 in words is "one trillion, three hundred thirty-four billion, thirty-three million, ninety-five thousand, six hundred ninety-three".
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