Base | Representation |
---|---|
bin | 10011011010011010100… |
… | …100011101111011100011 |
3 | 11201112101001122201021112 |
4 | 103122122210131323203 |
5 | 133324044434102203 |
6 | 2500502451213535 |
7 | 165244404235526 |
oct | 23323244357343 |
9 | 4645331581245 |
10 | 1334033112803 |
11 | 47483aa065a6 |
12 | 196664ba72ab |
13 | 98a4cc05a01 |
14 | 487d34c6bbd |
15 | 24a7bb656d8 |
hex | 1369a91dee3 |
1334033112803 has 2 divisors, whose sum is σ = 1334033112804. Its totient is φ = 1334033112802.
The previous prime is 1334033112781. The next prime is 1334033112817. The reversal of 1334033112803 is 3082113304331.
It is a strong prime.
It is an emirp because it is prime and its reverse (3082113304331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1334033112803 - 28 = 1334033112547 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1334033112803.
It is not a weakly prime, because it can be changed into another prime (1334033112103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 667016556401 + 667016556402.
It is an arithmetic number, because the mean of its divisors is an integer number (667016556402).
Almost surely, 21334033112803 is an apocalyptic number.
1334033112803 is a deficient number, since it is larger than the sum of its proper divisors (1).
1334033112803 is an equidigital number, since it uses as much as digits as its factorization.
1334033112803 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15552, while the sum is 32.
The spelling of 1334033112803 in words is "one trillion, three hundred thirty-four billion, thirty-three million, one hundred twelve thousand, eight hundred three".
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