Base | Representation |
---|---|
bin | 1100001000100000111001… |
… | …1101011111011001001111 |
3 | 1202020022221011220202000201 |
4 | 3002020032131133121033 |
5 | 3222032130211030132 |
6 | 44212300014234331 |
7 | 2544545551551211 |
oct | 302101635373117 |
9 | 52208834822021 |
10 | 13340411033167 |
11 | 4283700276369 |
12 | 15b55647b59a7 |
13 | 759cc2a71a6a |
14 | 34197216c5b1 |
15 | 1820349702e7 |
hex | c220e75f64f |
13340411033167 has 2 divisors, whose sum is σ = 13340411033168. Its totient is φ = 13340411033166.
The previous prime is 13340411032951. The next prime is 13340411033189. The reversal of 13340411033167 is 76133011404331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13340411033167 - 243 = 4544318010959 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13340411033267) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6670205516583 + 6670205516584.
It is an arithmetic number, because the mean of its divisors is an integer number (6670205516584).
Almost surely, 213340411033167 is an apocalyptic number.
13340411033167 is a deficient number, since it is larger than the sum of its proper divisors (1).
13340411033167 is an equidigital number, since it uses as much as digits as its factorization.
13340411033167 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54432, while the sum is 37.
Adding to 13340411033167 its reverse (76133011404331), we get a palindrome (89473422437498).
The spelling of 13340411033167 in words is "thirteen trillion, three hundred forty billion, four hundred eleven million, thirty-three thousand, one hundred sixty-seven".
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