Base | Representation |
---|---|
bin | 1100001000100000111100… |
… | …1011100110100111101111 |
3 | 1202020022222000122212221201 |
4 | 3002020033023212213233 |
5 | 3222032141304341031 |
6 | 44212301125310331 |
7 | 2544546056365642 |
oct | 302101713464757 |
9 | 52208860585851 |
10 | 13340423121391 |
11 | 4283707082433 |
12 | 15b55688653a7 |
13 | 759cc5414c62 |
14 | 3419739d7a59 |
15 | 182035a5bd61 |
hex | c220f2e69ef |
13340423121391 has 2 divisors, whose sum is σ = 13340423121392. Its totient is φ = 13340423121390.
The previous prime is 13340423121373. The next prime is 13340423121449. The reversal of 13340423121391 is 19312132404331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13340423121391 - 227 = 13340288903663 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13340423121391.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13340423121301) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6670211560695 + 6670211560696.
It is an arithmetic number, because the mean of its divisors is an integer number (6670211560696).
Almost surely, 213340423121391 is an apocalyptic number.
13340423121391 is a deficient number, since it is larger than the sum of its proper divisors (1).
13340423121391 is an equidigital number, since it uses as much as digits as its factorization.
13340423121391 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 46656, while the sum is 37.
The spelling of 13340423121391 in words is "thirteen trillion, three hundred forty billion, four hundred twenty-three million, one hundred twenty-one thousand, three hundred ninety-one".
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