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13340423121423 = 37019633538639
BaseRepresentation
bin1100001000100000111100…
…1011100110101000001111
31202020022222000122212222220
43002020033023212220033
53222032141304341143
644212301125310423
72544546056366016
oct302101713465017
952208860585886
1013340423121423
114283707082462
1215b5568865413
13759cc5414c88
143419739d7a7d
15182035a5bd83
hexc220f2e6a0f

13340423121423 has 8 divisors (see below), whose sum is σ = 17789765011200. Its totient is φ = 8892348322968.

The previous prime is 13340423121391. The next prime is 13340423121449. The reversal of 13340423121423 is 32412132404331.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13340423121423 - 25 = 13340423121391 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13340423121463) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 316748263 + ... + 316790376.

It is an arithmetic number, because the mean of its divisors is an integer number (2223720626400).

Almost surely, 213340423121423 is an apocalyptic number.

13340423121423 is a deficient number, since it is larger than the sum of its proper divisors (4449341889777).

13340423121423 is an equidigital number, since it uses as much as digits as its factorization.

13340423121423 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 633545661.

The product of its (nonzero) digits is 41472, while the sum is 33.

Adding to 13340423121423 its reverse (32412132404331), we get a palindrome (45752555525754).

The spelling of 13340423121423 in words is "thirteen trillion, three hundred forty billion, four hundred twenty-three million, one hundred twenty-one thousand, four hundred twenty-three".

Divisors: 1 3 7019 21057 633538639 1900615917 4446807707141 13340423121423