Base | Representation |
---|---|
bin | 1100001000100000111100… |
… | …1011100110101000110111 |
3 | 1202020022222000122220001101 |
4 | 3002020033023212220313 |
5 | 3222032141304341323 |
6 | 44212301125310531 |
7 | 2544546056366104 |
oct | 302101713465067 |
9 | 52208860586041 |
10 | 13340423121463 |
11 | 4283707082499 |
12 | 15b5568865447 |
13 | 759cc5414cb9 |
14 | 3419739d7aab |
15 | 182035a5bdad |
hex | c220f2e6a37 |
13340423121463 has 2 divisors, whose sum is σ = 13340423121464. Its totient is φ = 13340423121462.
The previous prime is 13340423121457. The next prime is 13340423121497. The reversal of 13340423121463 is 36412132404331.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13340423121463 is a prime.
It is a super-2 number, since 2×133404231214632 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13340423121763) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6670211560731 + 6670211560732.
It is an arithmetic number, because the mean of its divisors is an integer number (6670211560732).
Almost surely, 213340423121463 is an apocalyptic number.
13340423121463 is a deficient number, since it is larger than the sum of its proper divisors (1).
13340423121463 is an equidigital number, since it uses as much as digits as its factorization.
13340423121463 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 124416, while the sum is 37.
Adding to 13340423121463 its reverse (36412132404331), we get a palindrome (49752555525794).
The spelling of 13340423121463 in words is "thirteen trillion, three hundred forty billion, four hundred twenty-three million, one hundred twenty-one thousand, four hundred sixty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.078 sec. • engine limits •