Base | Representation |
---|---|
bin | 111110000111110000… |
… | …1000111000100100101 |
3 | 110202100011202211101211 |
4 | 1330033201013010211 |
5 | 4141203001333013 |
6 | 141141325351421 |
7 | 12431612021413 |
oct | 1741741070445 |
9 | 422304684354 |
10 | 133404324133 |
11 | 51638299253 |
12 | 21a30a08571 |
13 | c770282902 |
14 | 66576802b3 |
15 | 370bb7223d |
hex | 1f0f847125 |
133404324133 has 2 divisors, whose sum is σ = 133404324134. Its totient is φ = 133404324132.
The previous prime is 133404324127. The next prime is 133404324143. The reversal of 133404324133 is 331423404331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 94302425569 + 39101898564 = 307087^2 + 197742^2 .
It is a cyclic number.
It is not a de Polignac number, because 133404324133 - 29 = 133404323621 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 133404324095 and 133404324104.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133404324143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66702162066 + 66702162067.
It is an arithmetic number, because the mean of its divisors is an integer number (66702162067).
Almost surely, 2133404324133 is an apocalyptic number.
It is an amenable number.
133404324133 is a deficient number, since it is larger than the sum of its proper divisors (1).
133404324133 is an equidigital number, since it uses as much as digits as its factorization.
133404324133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 31104, while the sum is 31.
Adding to 133404324133 its reverse (331423404331), we get a palindrome (464827728464).
The spelling of 133404324133 in words is "one hundred thirty-three billion, four hundred four million, three hundred twenty-four thousand, one hundred thirty-three".
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