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13340445511 is a prime number
BaseRepresentation
bin11000110110010011…
…10000101101000111
31021102201101211220111
430123021300231013
5204310123224021
610043432013451
7651405626101
oct143311605507
937381354814
1013340445511
115726374188
122703831287
131347a91053
14907a6a571
1553129e8e1
hex31b270b47

13340445511 has 2 divisors, whose sum is σ = 13340445512. Its totient is φ = 13340445510.

The previous prime is 13340445493. The next prime is 13340445541. The reversal of 13340445511 is 11554404331.

13340445511 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13340445511 is a prime.

It is a super-2 number, since 2×133404455112 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13340445541) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6670222755 + 6670222756.

It is an arithmetic number, because the mean of its divisors is an integer number (6670222756).

Almost surely, 213340445511 is an apocalyptic number.

13340445511 is a deficient number, since it is larger than the sum of its proper divisors (1).

13340445511 is an equidigital number, since it uses as much as digits as its factorization.

13340445511 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 13340445511 its reverse (11554404331), we get a palindrome (24894849842).

The spelling of 13340445511 in words is "thirteen billion, three hundred forty million, four hundred forty-five thousand, five hundred eleven".