13341112144342 has 4 divisors (see below), whose sum is σ = 20011668216516. Its totient is φ = 6670556072170.

The previous prime is 13341112144291. The next prime is 13341112144391. The reversal of 13341112144342 is 24344121114331.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×13341112144342² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13341112144298 and 13341112144307.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3335278036084 + ... + 3335278036087.

It is an arithmetic number, because the mean of its divisors is an integer number (5002917054129).

Almost surely, 2^{13341112144342} is an apocalyptic number.

13341112144342 is a deficient number, since it is larger than the sum of its proper divisors (6670556072174).

13341112144342 is an equidigital number, since it uses as much as digits as its factorization.

13341112144342 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6670556072173.

The product of its digits is 27648, while the sum is 34.

Adding to 13341112144342 its reverse (24344121114331), we get a palindrome (37685233258673).

The spelling of 13341112144342 in words is "thirteen trillion, three hundred forty-one billion, one hundred twelve million, one hundred forty-four thousand, three hundred forty-two".