Base | Representation |
---|---|
bin | 1100001000100011100001… |
… | …0000101110100001011011 |
3 | 1202020101202001112022212202 |
4 | 3002020320100232201123 |
5 | 3222040044224032311 |
6 | 44212453345400415 |
7 | 2544602125514312 |
oct | 302107020564133 |
9 | 52211661468782 |
10 | 13341112330331 |
11 | 4283a301212a5 |
12 | 15b571b63910b |
13 | 75a0a51466b6 |
14 | 3419db363279 |
15 | 1820762ebe3b |
hex | c223842e85b |
13341112330331 has 2 divisors, whose sum is σ = 13341112330332. Its totient is φ = 13341112330330.
The previous prime is 13341112330261. The next prime is 13341112330391. The reversal of 13341112330331 is 13303321114331.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13341112330331 is a prime.
It is a super-2 number, since 2×133411123303312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13341112330294 and 13341112330303.
It is not a weakly prime, because it can be changed into another prime (13341112330391) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6670556165165 + 6670556165166.
It is an arithmetic number, because the mean of its divisors is an integer number (6670556165166).
Almost surely, 213341112330331 is an apocalyptic number.
13341112330331 is a deficient number, since it is larger than the sum of its proper divisors (1).
13341112330331 is an equidigital number, since it uses as much as digits as its factorization.
13341112330331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5832, while the sum is 29.
Adding to 13341112330331 its reverse (13303321114331), we get a palindrome (26644433444662).
The spelling of 13341112330331 in words is "thirteen trillion, three hundred forty-one billion, one hundred twelve million, three hundred thirty thousand, three hundred thirty-one".
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