1334111324130 has 48 divisors (see below), whose sum is σ = 3735511710840. Its totient is φ = 328396633344.

The previous prime is 1334111324089. The next prime is 1334111324137. The reversal of 1334111324130 is 314231114331.

1334111324130 is a `hidden beast` number, since 1 + 3 + 3 + 411 + 1 + 3 + 241 + 3 + 0 = 666.

It can be written as a sum of positive squares in 4 ways, for example, as 415866345129 + 918244979001 = 644877^2 + 958251^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1334111324094 and 1334111324103.

It is not an unprimeable number, because it can be changed into a prime (1334111324137) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 570131875 + ... + 570134214.

Almost surely, 2^{1334111324130} is an apocalyptic number.

1334111324130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1334111324130 is an abundant number, since it is smaller than the sum of its proper divisors (2401400386710).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1334111324130 is a wasteful number, since it uses less digits than its factorization.

1334111324130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1140266115 (or 1140266112 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 27.

Adding to 1334111324130 its reverse (314231114331), we get a palindrome (1648342438461).

It can be divided in two parts, 133411 and 1324130, that added together give a palindrome (1457541).

The spelling of 1334111324130 in words is "one trillion, three hundred thirty-four billion, one hundred eleven million, three hundred twenty-four thousand, one hundred thirty".