Base | Representation |
---|---|
bin | 11000110110011000… |
… | …10111111011100111 |
3 | 1021102202200122111101 |
4 | 30123030113323213 |
5 | 204310312133341 |
6 | 10043454420531 |
7 | 651414511054 |
oct | 143314277347 |
9 | 37382618441 |
10 | 13341130471 |
11 | 57267a1869 |
12 | 2703b01747 |
13 | 1347c70a56 |
14 | 907ba802b |
15 | 531387831 |
hex | 31b317ee7 |
13341130471 has 2 divisors, whose sum is σ = 13341130472. Its totient is φ = 13341130470.
The previous prime is 13341130399. The next prime is 13341130483. The reversal of 13341130471 is 17403114331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13341130471 - 225 = 13307576039 is a prime.
It is a super-3 number, since 3×133411304713 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13341130571) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6670565235 + 6670565236.
It is an arithmetic number, because the mean of its divisors is an integer number (6670565236).
Almost surely, 213341130471 is an apocalyptic number.
13341130471 is a deficient number, since it is larger than the sum of its proper divisors (1).
13341130471 is an equidigital number, since it uses as much as digits as its factorization.
13341130471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3024, while the sum is 28.
The spelling of 13341130471 in words is "thirteen billion, three hundred forty-one million, one hundred thirty thousand, four hundred seventy-one".
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