13341141100411 has 2 divisors, whose sum is σ = 13341141100412. Its totient is φ = 13341141100410.

The previous prime is 13341141100393. The next prime is 13341141100421. The reversal of 13341141100411 is 11400114114331.

It is a strong prime.

It is an emirp because it is prime and its reverse (11400114114331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13341141100411 - 2⁹ = 13341141099899 is a prime.

It is a super-2 number, since 2×13341141100411² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13341141100421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6670570550205 + 6670570550206.

It is an arithmetic number, because the mean of its divisors is an integer number (6670570550206).

Almost surely, 2^{13341141100411} is an apocalyptic number.

13341141100411 is a deficient number, since it is larger than the sum of its proper divisors (1).

13341141100411 is an equidigital number, since it uses as much as digits as its factorization.

13341141100411 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 25.

Adding to 13341141100411 its reverse (11400114114331), we get a palindrome (24741255214742).

The spelling of 13341141100411 in words is "thirteen trillion, three hundred forty-one billion, one hundred forty-one million, one hundred thousand, four hundred eleven".