Base | Representation |
---|---|
bin | 111110001000000001… |
… | …1000001110000010011 |
3 | 110202100210111112201111 |
4 | 1330100003001300103 |
5 | 4141212240342001 |
6 | 141142244114151 |
7 | 12432050422141 |
oct | 1742003016023 |
9 | 422323445644 |
10 | 133413215251 |
11 | 51642311288 |
12 | 21a33995957 |
13 | c772076824 |
14 | 6658916591 |
15 | 370c82b851 |
hex | 1f100c1c13 |
133413215251 has 2 divisors, whose sum is σ = 133413215252. Its totient is φ = 133413215250.
The previous prime is 133413215237. The next prime is 133413215261. The reversal of 133413215251 is 152512314331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133413215251 - 27 = 133413215123 is a prime.
It is not a weakly prime, because it can be changed into another prime (133413215261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66706607625 + 66706607626.
It is an arithmetic number, because the mean of its divisors is an integer number (66706607626).
Almost surely, 2133413215251 is an apocalyptic number.
133413215251 is a deficient number, since it is larger than the sum of its proper divisors (1).
133413215251 is an equidigital number, since it uses as much as digits as its factorization.
133413215251 is an evil number, because the sum of its binary digits is even.
The product of its digits is 10800, while the sum is 31.
Adding to 133413215251 its reverse (152512314331), we get a palindrome (285925529582).
The spelling of 133413215251 in words is "one hundred thirty-three billion, four hundred thirteen million, two hundred fifteen thousand, two hundred fifty-one".
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