Base | Representation |
---|---|
bin | 111110001000000001… |
… | …1000001110000000101 |
3 | 110202100210111112200222 |
4 | 1330100003001300011 |
5 | 4141212240341422 |
6 | 141142244114125 |
7 | 12432050422121 |
oct | 1742003016005 |
9 | 422323445628 |
10 | 133413215237 |
11 | 51642311275 |
12 | 21a33995945 |
13 | c772076813 |
14 | 6658916581 |
15 | 370c82b842 |
hex | 1f100c1c05 |
133413215237 has 2 divisors, whose sum is σ = 133413215238. Its totient is φ = 133413215236.
The previous prime is 133413215207. The next prime is 133413215251. The reversal of 133413215237 is 732512314331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 113165632801 + 20247582436 = 336401^2 + 142294^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133413215237 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 133413215197 and 133413215206.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133413215207) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66706607618 + 66706607619.
It is an arithmetic number, because the mean of its divisors is an integer number (66706607619).
Almost surely, 2133413215237 is an apocalyptic number.
It is an amenable number.
133413215237 is a deficient number, since it is larger than the sum of its proper divisors (1).
133413215237 is an equidigital number, since it uses as much as digits as its factorization.
133413215237 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 45360, while the sum is 35.
Adding to 133413215237 its reverse (732512314331), we get a palindrome (865925529568).
The spelling of 133413215237 in words is "one hundred thirty-three billion, four hundred thirteen million, two hundred fifteen thousand, two hundred thirty-seven".
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