Base | Representation |
---|---|
bin | 111110001000000001… |
… | …1011010001100000011 |
3 | 110202100210200122000011 |
4 | 1330100003122030003 |
5 | 4141212302042311 |
6 | 141142250205351 |
7 | 12432051320002 |
oct | 1742003321403 |
9 | 422323618004 |
10 | 133413315331 |
11 | 5164237a49a |
12 | 21a33a23857 |
13 | c7720b024a |
14 | 6658940c39 |
15 | 370c84b321 |
hex | 1f100da303 |
133413315331 has 2 divisors, whose sum is σ = 133413315332. Its totient is φ = 133413315330.
The previous prime is 133413315251. The next prime is 133413315337. The reversal of 133413315331 is 133513314331.
It is a strong prime.
It is an emirp because it is prime and its reverse (133513314331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 133413315331 - 211 = 133413313283 is a prime.
It is a super-2 number, since 2×1334133153312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 133413315293 and 133413315302.
It is not a weakly prime, because it can be changed into another prime (133413315337) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66706657665 + 66706657666.
It is an arithmetic number, because the mean of its divisors is an integer number (66706657666).
Almost surely, 2133413315331 is an apocalyptic number.
133413315331 is a deficient number, since it is larger than the sum of its proper divisors (1).
133413315331 is an equidigital number, since it uses as much as digits as its factorization.
133413315331 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 14580, while the sum is 31.
Adding to 133413315331 its reverse (133513314331), we get a palindrome (266926629662).
The spelling of 133413315331 in words is "one hundred thirty-three billion, four hundred thirteen million, three hundred fifteen thousand, three hundred thirty-one".
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