Base | Representation |
---|---|
bin | 111110001000000001… |
… | …1011010001010110011 |
3 | 110202100210200121220012 |
4 | 1330100003122022303 |
5 | 4141212302042001 |
6 | 141142250205135 |
7 | 12432051316526 |
oct | 1742003321263 |
9 | 422323617805 |
10 | 133413315251 |
11 | 5164237a427 |
12 | 21a33a237ab |
13 | c7720b01b8 |
14 | 6658940bbd |
15 | 370c84b2bb |
hex | 1f100da2b3 |
133413315251 has 2 divisors, whose sum is σ = 133413315252. Its totient is φ = 133413315250.
The previous prime is 133413315179. The next prime is 133413315331. The reversal of 133413315251 is 152513314331.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133413315251 is a prime.
It is a super-2 number, since 2×1334133152512 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (133413215251) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66706657625 + 66706657626.
It is an arithmetic number, because the mean of its divisors is an integer number (66706657626).
Almost surely, 2133413315251 is an apocalyptic number.
133413315251 is a deficient number, since it is larger than the sum of its proper divisors (1).
133413315251 is an equidigital number, since it uses as much as digits as its factorization.
133413315251 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 16200, while the sum is 32.
Adding to 133413315251 its reverse (152513314331), we get a palindrome (285926629582).
The spelling of 133413315251 in words is "one hundred thirty-three billion, four hundred thirteen million, three hundred fifteen thousand, two hundred fifty-one".
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