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133415265419 is a prime number
BaseRepresentation
bin111110001000000101…
…0110110010010001011
3110202100221100201000122
41330100022312102023
54141213301443134
6141142400053455
712432104021252
oct1742012662213
9422327321018
10133415265419
1151643491637
1221a3460428b
13c772613a47
146658ccb799
15370cad402e
hex1f102b648b

133415265419 has 2 divisors, whose sum is σ = 133415265420. Its totient is φ = 133415265418.

The previous prime is 133415265343. The next prime is 133415265421. The reversal of 133415265419 is 914562514331.

It is a strong prime.

It is an emirp because it is prime and its reverse (914562514331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 133415265419 - 220 = 133414216843 is a prime.

It is a super-2 number, since 2×1334152654192 (a number of 23 digits) contains 22 as substring.

Together with 133415265421, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 133415265419.

It is not a weakly prime, because it can be changed into another prime (133415265619) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66707632709 + 66707632710.

It is an arithmetic number, because the mean of its divisors is an integer number (66707632710).

Almost surely, 2133415265419 is an apocalyptic number.

133415265419 is a deficient number, since it is larger than the sum of its proper divisors (1).

133415265419 is an equidigital number, since it uses as much as digits as its factorization.

133415265419 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 388800, while the sum is 44.

The spelling of 133415265419 in words is "one hundred thirty-three billion, four hundred fifteen million, two hundred sixty-five thousand, four hundred nineteen".