133420224401 has 2 divisors, whose sum is σ = 133420224402. Its totient is φ = 133420224400.

The previous prime is 133420224359. The next prime is 133420224403. The reversal of 133420224401 is 104422024331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 126152832400 + 7267392001 = 355180^2 + 85249^2 .

It is an emirp because it is prime and its reverse (104422024331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 133420224401 - 2¹⁴ = 133420208017 is a prime.

Together with 133420224403, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (133420224403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66710112200 + 66710112201.

It is an arithmetic number, because the mean of its divisors is an integer number (66710112201).

Almost surely, 2^133420224401 is an apocalyptic number.

It is an amenable number.

133420224401 is a deficient number, since it is larger than the sum of its proper divisors (1).

133420224401 is an equidigital number, since it uses as much as digits as its factorization.

133420224401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4608, while the sum is 26.

Adding to 133420224401 its reverse (104422024331), we get a palindrome (237842248732).

The spelling of 133420224401 in words is "one hundred thirty-three billion, four hundred twenty million, two hundred twenty-four thousand, four hundred one".