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133421114013001 is a prime number
BaseRepresentation
bin11110010101100010000110…
…000110110011010101001001
3122111101221012211120221000021
4132111202012012303111021
5114441432420141404001
61151432451424140441
740050233404052023
oct3625420606632511
9574357184527007
10133421114013001
113956a638640821
1212b69aa5167721
13595a731b47029
1424d388b489013
1510658c9154ba1
hex7958861b3549

133421114013001 has 2 divisors, whose sum is σ = 133421114013002. Its totient is φ = 133421114013000.

The previous prime is 133421114012993. The next prime is 133421114013013. The reversal of 133421114013001 is 100310411124331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 119122468376976 + 14298645636025 = 10914324^2 + 3781355^2 .

It is a cyclic number.

It is not a de Polignac number, because 133421114013001 - 23 = 133421114012993 is a prime.

It is not a weakly prime, because it can be changed into another prime (133421114013091) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66710557006500 + 66710557006501.

It is an arithmetic number, because the mean of its divisors is an integer number (66710557006501).

Almost surely, 2133421114013001 is an apocalyptic number.

It is an amenable number.

133421114013001 is a deficient number, since it is larger than the sum of its proper divisors (1).

133421114013001 is an equidigital number, since it uses as much as digits as its factorization.

133421114013001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 133421114013001 its reverse (100310411124331), we get a palindrome (233731525137332).

The spelling of 133421114013001 in words is "one hundred thirty-three trillion, four hundred twenty-one billion, one hundred fourteen million, thirteen thousand, one".