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133421122412353 is a prime number
BaseRepresentation
bin11110010101100010000110…
…100110110101111101000001
3122111101221020102101122202101
4132111202012212311331001
5114441432424314143403
61151432452324150401
740050233535333646
oct3625420646657501
9574357212348671
10133421122412353
113956a642358336
1212b69aa7b38401
13595a7337c8169
1424d388c633dcd
1510658c9c6371d
hex7958869b5f41

133421122412353 has 2 divisors, whose sum is σ = 133421122412354. Its totient is φ = 133421122412352.

The previous prime is 133421122412327. The next prime is 133421122412423. The reversal of 133421122412353 is 353214221124331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 105632494506289 + 27788627906064 = 10277767^2 + 5271492^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133421122412353 is a prime.

It is not a weakly prime, because it can be changed into another prime (133421122452353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66710561206176 + 66710561206177.

It is an arithmetic number, because the mean of its divisors is an integer number (66710561206177).

Almost surely, 2133421122412353 is an apocalyptic number.

It is an amenable number.

133421122412353 is a deficient number, since it is larger than the sum of its proper divisors (1).

133421122412353 is an equidigital number, since it uses as much as digits as its factorization.

133421122412353 is an evil number, because the sum of its binary digits is even.

The product of its digits is 103680, while the sum is 37.

Adding to 133421122412353 its reverse (353214221124331), we get a palindrome (486635343536684).

The spelling of 133421122412353 in words is "one hundred thirty-three trillion, four hundred twenty-one billion, one hundred twenty-two million, four hundred twelve thousand, three hundred fifty-three".