Base | Representation |
---|---|
bin | 11110010101100010000110… |
… | …100110110101111110000111 |
3 | 122111101221020102101122211222 |
4 | 132111202012212311332013 |
5 | 114441432424314144143 |
6 | 1151432452324150555 |
7 | 40050233535334106 |
oct | 3625420646657607 |
9 | 574357212348758 |
10 | 133421122412423 |
11 | 3956a64235839a |
12 | 12b69aa7b3845b |
13 | 595a7337c81c1 |
14 | 24d388c63403d |
15 | 10658c9c63768 |
hex | 7958869b5f87 |
133421122412423 has 2 divisors, whose sum is σ = 133421122412424. Its totient is φ = 133421122412422.
The previous prime is 133421122412353. The next prime is 133421122412449. The reversal of 133421122412423 is 324214221124331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133421122412423 - 28 = 133421122412167 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133421122412483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66710561206211 + 66710561206212.
It is an arithmetic number, because the mean of its divisors is an integer number (66710561206212).
Almost surely, 2133421122412423 is an apocalyptic number.
133421122412423 is a deficient number, since it is larger than the sum of its proper divisors (1).
133421122412423 is an equidigital number, since it uses as much as digits as its factorization.
133421122412423 is an evil number, because the sum of its binary digits is even.
The product of its digits is 55296, while the sum is 35.
Adding to 133421122412423 its reverse (324214221124331), we get a palindrome (457635343536754).
The spelling of 133421122412423 in words is "one hundred thirty-three trillion, four hundred twenty-one billion, one hundred twenty-two million, four hundred twelve thousand, four hundred twenty-three".
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