13342120331 has 2 divisors, whose sum is σ = 13342120332. Its totient is φ = 13342120330.

The previous prime is 13342120313. The next prime is 13342120333. The reversal of 13342120331 is 13302124331.

Together with previous prime (13342120313) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is an emirp because it is prime and its reverse (13302124331) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13342120331 is a prime.

It is a super-2 number, since 2×13342120331² (a number of 21 digits) contains 22 as substring.

Together with 13342120333, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13342120297 and 13342120306.

It is not a weakly prime, because it can be changed into another prime (13342120333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6671060165 + 6671060166.

It is an arithmetic number, because the mean of its divisors is an integer number (6671060166).

Almost surely, 2^13342120331 is an apocalyptic number.

13342120331 is a deficient number, since it is larger than the sum of its proper divisors (1).

13342120331 is an equidigital number, since it uses as much as digits as its factorization.

13342120331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 13342120331 its reverse (13302124331), we get a palindrome (26644244662).

The spelling of 13342120331 in words is "thirteen billion, three hundred forty-two million, one hundred twenty thousand, three hundred thirty-one".