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133421204300 = 22521334212043
BaseRepresentation
bin111110001000010000…
…1100000001101001100
3110202101100112102122012
41330100201200031030
54141221312014200
6141143131240352
712432205344626
oct1742041401514
9422340472565
10133421204300
11516468785aa
1221a365a90b8
13c773912c87
1466599d5c16
15370d3a8a35
hex1f1086034c

133421204300 has 18 divisors (see below), whose sum is σ = 289524013548. Its totient is φ = 53368481680.

The previous prime is 133421204299. The next prime is 133421204303. The reversal of 133421204300 is 3402124331.

It is a super-3 number, since 3×1334212043003 (a number of 34 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (133421204303) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 667105922 + ... + 667106121.

Almost surely, 2133421204300 is an apocalyptic number.

133421204300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

133421204300 is an abundant number, since it is smaller than the sum of its proper divisors (156102809248).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133421204300 is a wasteful number, since it uses less digits than its factorization.

133421204300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1334212057 (or 1334212050 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 133421204300 its reverse (3402124331), we get a palindrome (136823328631).

The spelling of 133421204300 in words is "one hundred thirty-three billion, four hundred twenty-one million, two hundred four thousand, three hundred".

Divisors: 1 2 4 5 10 20 25 50 100 1334212043 2668424086 5336848172 6671060215 13342120430 26684240860 33355301075 66710602150 133421204300